Logout link in layout

[emmexx-2]

I'd like to put a logout link in my default layout. The link should be
there only when a user has already logged in.
I put the following code in my app/views/layouts/default.ctp:

if ($this->Auth->user())
        echo $html->link('Logout', array('controller' => 'Users',
'action'=>'logout'));

but, of course, cake didn't like and screamed in horror:

Notice (8): Undefined property:  View::$Auth [APP/views/elements/
logout.ctp, line 3]

Fatal error: Call to a member function user() on a non-object in /app/
views/elements/logout.ctp on line 3

Is there a way to accomplish that?

Thank you and Merry Christmas!

   maxx

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[harake-2]

in you app_controller.php, put this
public function beforeRender() {
        if (!array_key_exists('requested', $this->params)) {
                $user = $this->Session->read($this->Auth->sessionKey);
                $this->set(compact('user'));
        }
}

and in the layout put this

if (!empty($user))
        echo $html->link('Logout', array('controller' => 'Users',
'action'=>'logout'));

and the happy new year
On Dec 24, 4:46 am, emmexx <[hidden email]> wrote:

> I'd like to put a logout link in my default layout. The link should be
> there only when a user has already logged in.
> I put the following code in my app/views/layouts/default.ctp:
>
> if ($this->Auth->user())
>         echo $html->link('Logout', array('controller' => 'Users',
> 'action'=>'logout'));
>
> but, of course, cake didn't like and screamed in horror:
>
> Notice (8): Undefined property:  View::$Auth [APP/views/elements/
> logout.ctp, line 3]
>
> Fatal error: Call to a member function user() on a non-object in /app/
> views/elements/logout.ctp on line 3
>
> Is there a way to accomplish that?
>
> Thank you and Merry Christmas!
>
>    maxx

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[Edinei L. Cipriani]

If(isset($this->Session->read('User.id'))):
> echo $html->link('Logout', array('controller' => 'Users',
> 'action'=>'logout'));

endif;



happy christmas


Em 24/12/2009, às 07:46, emmexx escreveu:

> I'd like to put a logout link in my default layout. The link should be
> there only when a user has already logged in.
> I put the following code in my app/views/layouts/default.ctp:
>
> if ($this->Auth->user())
> echo $html->link('Logout', array('controller' => 'Users',
> 'action'=>'logout'));
>
> but, of course, cake didn't like and screamed in horror:
>
> Notice (8): Undefined property:  View::$Auth [APP/views/elements/
> logout.ctp, line 3]
>
> Fatal error: Call to a member function user() on a non-object in /app/
> views/elements/logout.ctp on line 3
>
> Is there a way to accomplish that?
>
> Thank you and Merry Christmas!
>
>   maxx
>
> Check out the new CakePHP Questions site http://cakeqs.org and help  
> others with their CakePHP related questions.
>
> You received this message because you are subscribed to the Google  
> Groups "CakePHP" group.
> To post to this group, send email to [hidden email]
> To unsubscribe from this group, send email to
> [hidden email] For more options, visit this  
> group at http://groups.google.com/group/cake-php?hl=en

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[stefano-2-3]

if($Session->read("User.id")) {
...
}

On Thu, Dec 24, 2009 at 8:30 AM, Edinei Luis Cipriani
<[hidden email]> wrote:

> If(isset($this->Session->read('User.id'))):
>> echo $html->link('Logout', array('controller' => 'Users',
>> 'action'=>'logout'));
>
> endif;
>
>
>
> happy christmas
>
>
> Em 24/12/2009, às 07:46, emmexx escreveu:
>
>> I'd like to put a logout link in my default layout. The link should be
>> there only when a user has already logged in.
>> I put the following code in my app/views/layouts/default.ctp:
>>
>> if ($this->Auth->user())
>>       echo $html->link('Logout', array('controller' => 'Users',
>> 'action'=>'logout'));
>>
>> but, of course, cake didn't like and screamed in horror:
>>
>> Notice (8): Undefined property:  View::$Auth [APP/views/elements/
>> logout.ctp, line 3]
>>
>> Fatal error: Call to a member function user() on a non-object in /app/
>> views/elements/logout.ctp on line 3
>>
>> Is there a way to accomplish that?
>>
>> Thank you and Merry Christmas!
>>
>>   maxx
>>
>> Check out the new CakePHP Questions site http://cakeqs.org and help
>> others with their CakePHP related questions.
>>
>> You received this message because you are subscribed to the Google
>> Groups "CakePHP" group.
>> To post to this group, send email to [hidden email]
>> To unsubscribe from this group, send email to
>> [hidden email] For more options, visit this
>> group at http://groups.google.com/group/cake-php?hl=en
>
> Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions.
>
> You received this message because you are subscribed to the Google Groups "CakePHP" group.
> To post to this group, send email to [hidden email]
> To unsubscribe from this group, send email to
> [hidden email] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
>

--
Stefano Salvatori M.
http://stefano.salvatori.cl/

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[euromark (munich)]

If($this->Session->read('User.id'))
would only be appropriate in cakephp 1.3! (in the view)


On 24 Dez., 12:40, stefano <[hidden email]> wrote:

> if($Session->read("User.id")) {
> ...
>
> }
>
> On Thu, Dec 24, 2009 at 8:30 AM, Edinei Luis Cipriani
>
>
>
> <[hidden email]> wrote:
> > If(isset($this->Session->read('User.id'))):
> >> echo $html->link('Logout', array('controller' => 'Users',
> >> 'action'=>'logout'));
>
> > endif;
>
> > happy christmas
>
> > Em 24/12/2009, às 07:46, emmexx escreveu:
>
> >> I'd like to put a logout link in my default layout. The link should be
> >> there only when a user has already logged in.
> >> I put the following code in my app/views/layouts/default.ctp:
>
> >> if ($this->Auth->user())
> >>       echo $html->link('Logout', array('controller' => 'Users',
> >> 'action'=>'logout'));
>
> >> but, of course, cake didn't like and screamed in horror:
>
> >> Notice (8): Undefined property:  View::$Auth [APP/views/elements/
> >> logout.ctp, line 3]
>
> >> Fatal error: Call to a member function user() on a non-object in /app/
> >> views/elements/logout.ctp on line 3
>
> >> Is there a way to accomplish that?
>
> >> Thank you and Merry Christmas!
>
> >>   maxx
>
> >> Check out the new CakePHP Questions sitehttp://cakeqs.organd help
> >> others with their CakePHP related questions.
>
> >> You received this message because you are subscribed to the Google
> >> Groups "CakePHP" group.
> >> To post to this group, send email to [hidden email]
> >> To unsubscribe from this group, send email to
> >> [hidden email] For more options, visit this
> >> group athttp://groups.google.com/group/cake-php?hl=en
>
> > Check out the new CakePHP Questions sitehttp://cakeqs.organd help others with their CakePHP related questions.
>
> > You received this message because you are subscribed to the Google Groups "CakePHP" group.
> > To post to this group, send email to [hidden email]
> > To unsubscribe from this group, send email to
> > [hidden email] For more options, visit this group athttp://groups.google.com/group/cake-php?hl=en
>
> --
> Stefano Salvatori M.http://stefano.salvatori.cl/

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[Kani-3]

How to do this in cakephp 1.2.5

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