To load the form with AJAX, call the edit action, passing the ID, with
JQuery's load(). Use the same URL that you would in a link, in other
words.
If you only want the form to be loaded, and not the regular edit view,
put the form itself inside an element. The add & edit views then load
the form with $this->element(). Use a switch to branch based on the
action:
form.ctp:
switch ($this->params['action'])
{
case 'admin_edit':
echo $this->Form->create('Post', array('action' => 'edit'));
echo $this->Form->hidden('Post.id');
break;
case 'admin_add':
default:
echo $this->Form->create('Post', array('action' => 'add'));
}
// etc.
In the controller, test to see if it's an AJAX request. If it is, set
the viewPath to point to the elements directory, then render just the
form, not the full edit view.
function beforeFilter()
{
parent::beforeFilter();
if ($this->RequestHandler->isAjax())
{
Configure::write('debug', 0);
$this->layout = 'ajax';
}
}
public function edit($id = null)
{
// other stuff ...
if ($this->RequestHandler->isAjax())
{
$this->viewPath = 'elements'.DS.'your_controller_name';
$this->render('form');
}
}
On Wed, May 23, 2012 at 6:06 PM, femi oni <
[hidden email]> wrote:
> I have a jquery page and am using load() function to load objects to
> that page but now i need to load an edit form with the existing values
> to the page. do i load the view of the object and then use
> requestAction to get the existing data?
>
> --
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Our newest site for the community: CakePHP Video Tutorials
http://tv.cakephp.org
Check out the new CakePHP Questions site
http://ask.cakephp.org and help others with their CakePHP related questions.
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